Justdial Placement Papers with Solutions

Justdial Online Test Placement Papers with Solutions

if RED=6702 then GREEN=??
RED=6702
D=4+2=6
E=5+2=7
R=18+2=20
so DER=6702 in reverse manner
so green will be
N=14+2=16
E=5+2=7
E=5+2=7
R=18+2=20
G=7+2=9
now write it in reverse
NEERG=6177029



Opposite Meaning for AGRARIAN
a) suburban
b) cosmic
c) areal
d) urban
Ans d)urban

Kirubha gives a pen to karan on first day. The next day, it will be doubled and so on. Totally how many pens are given in 10 days?
Formula = (2^n)-1.
Logic:
1st day  = 1            =1              =(2^1) -1
2nd day = 1+2     =3           = (2^2) -1
3rd day = 1+2+4=7         = (2^3)-1
..........
10th day=(2^10)-1 =1023.









101,100,?,87,71,46
a)34
b)54
c)44
d)64
Ans-
101-1^2=100
100-2^2=96
96-3^2=87
87-4^2=71
71-5^2=46


88,64,24,     find the next number in the series
8*8=64
6*4=24
2*4=8
ans=8


A women says her age is 25 excluding saturdays and sundays.Now what is her current age?
Excluding Saturday and Sunday we have 5 days in a week.So actual age = 25 * 7/5 = 35


 0,4,18,48,100,?
1^3-1^2=0
2^3-2^2=4
3^3-3^2=18
4^3-4^2=48
5^3-5^2=100
6^3-6^2=180
ans 180


The age of Saroja is 2 times the age of vijya. the age of revathi is 20 years less than vijya . if revathi's current age is 39 . what is the age of vijya and saroja ?
Let vijaya's age be x
saroja's age is 2 times of vijaya = 2x
given revathi is 20 yrs less than vijaya = x-20
and revathi's current age is 39
so,  x-20=39
         x=59
so vijaya's age is:   59
      saroja's age is 2*59=   118



What is synonym of scolding....?
A.  Praising
B.  Abusing
C.  Supporting
D.  None of these
B.Abusing


a scale can only weigh items that are more than 70 kg, so 5 boys had to be weighed in pairs.
the 10 weights recorded were: 86,92,96,100,104,109,110,113,119,127.
what is the weight of the second heaviest boy?
(explain your logic)

ANS Sum of weights of all boys = (86+92+96+....+127)/4 = 264.
Let A be weight of lightest boy, B be weight of 2nd lightest boy and so on (upto E)
A+B=86; D+E=127
Weight of  3rd heaviest/lightest boy = C = 264 - (127+86) = 51.
Second smallest weight combination is 92. This must be sum of weights of lightest and 3rd lightest boys.
(i.e) A+C=92
Since C=51, A =92.
Since A+B=86, B=45
Third smallest weight combination may be B + C or A + D
Clearly B=45 and C=51, therefore B + C =96
Thus B + C  is the 3rd smallest weight combination.
Fourth smallest weight combination must be A+D
A+D=100
Since A=41, it follows D=59.
Since D+E=127, it follows E=68.
The values can be verified using the given weight combinations.
Answer: Weight of second heaviest boy is 59.

Find the missing term(s) in the series given  below:
0.5, 2.5, 7.5, ?, 23.5, 34.5, 47.5

11.5
12.5
14.5
13.5